Pearson Edexcel International GCSE (9–1) · CHEMISTRY · Chapter
Chemical Formulae, Equations and Calculations Part 2
144 practice questions
Topics covered
- Calculations involving gas volumes19 practice questions
- Calculating the volume of a certain number of moles19 practice questions
- Using the molar volume in calculations with chemical equations19 practice questions
- Concentrations of solutions19 practice questions
- Calculations with equations involving solutions19 practice questions
- The standard calculation19 practice questions
- Reversing the calculations20 practice questions
Practice questions
31–40 of 61 · Normal
Question 31
2 marks · Normal
Answer and see the solution →Calculate the concentration in mol/dm³ of a solution containing 5.60 g of potassium hydroxide (KOH, Ar: K = 39, O = 16, H = 1) in 500 cm³ of solution.
Question 32
4 marks · Normal
Answer and see the solution →(a)[2 marks]A solution has a concentration of 1.5 mol/dm³. What is the amount (in mol) of solute in 750 cm³ of this solution?
(b)[2 marks]Describe how you would prepare 750 cm³ of this solution from a 3.0 mol/dm³ solution.
Question 33
2 marks · Normal
Answer and see the solution →Calculate the number of moles of potassium nitrate, KNO₃, in 25 cm³ of a solution with concentration 0.40 mol/dm³.
Question 34
4 marks · Normal
Answer and see the solution →A reaction between barium chloride and sodium sulfate is shown by the equation:
(a)[2 marks]Calculate the number of moles of Na₂SO₄ in 40 cm³ of solution with concentration 0.10 mol/dm³.
(b)[2 marks]Use the balanced equation to determine the number of moles of BaCl₂ that react with this amount of Na₂SO₄.
Question 35
3 marks · Normal
Answer and see the solution →What mass of magnesium sulfate, MgSO₄, is produced when 25 cm³ of 0.50 mol/dm³ sulfuric acid, H₂SO₄, reacts with excess magnesium oxide, MgO?
(Ar: Mg = 24, S = 32, O = 16)
Question 36
3 marks · Normal
Answer and see the solution →A student dissolves 0.015 mol of silver nitrate in 100 cm³ of water.
Explain how to work out the concentration of this solution in mol/dm³. Show your calculation.
Question 37
4 marks · Normal
Answer and see the solution →A student carries out a reaction between sodium hydroxide and hydrochloric acid:
Results table Experiment Volume of NaOH (cm³) Concentration of NaOH (mol/dm³) 1 20 0.25 2 15 0.25 3 25 0.50 (a)[2 marks]For experiment 2, calculate the number of moles of NaOH used.
(b)[2 marks]Using the equation, state the number of moles of HCl needed to react with the NaOH in experiment 2 and explain your answer.
Question 38
1 mark · Normal
Answer and check →Which of the following shows the correct mass of sodium chloride produced when 0.020 mol of hydrochloric acid, HCl, reacts with excess sodium hydroxide, NaOH? (Ar: Na = 23, Cl = 35.5)
- A.0.585 g
- B.1.17 g
- C.2.34 g
- D.0.2925 g
Question 39
2 marks · Normal
Answer and see the solution →Calculate the number of moles of copper(II) sulfate in 200 cm³ of solution with concentration 0.050 mol/dm³.
Question 40
4 marks · Normal
Answer and see the solution →Potassium permanganate reacts with iron(II) sulfate as shown:
(a)[2 marks]Calculate the number of moles of FeSO₄ in 50 cm³ of 0.20 mol/dm³ solution.
(b)[2 marks]Use the equation to find the number of moles of KMnO₄ needed to react with this amount of FeSO₄.