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Pearson Edexcel International GCSE (9–1) · CHEMISTRY · Chapter

Covalent Bonding

68 practice questions

Topics covered

Practice questions

51–60 of 68

  1. Question 51

    4 marks · Normal

    The table shows the melting points and hardness for three forms of carbon.

    Properties of carbon allotropes
    AllotropeMelting point/°CHardness
    Diamond3550Very hard
    Graphite3600Soft
    C60 fullerene280Soft
    (a)

    Using only the data, identify which allotrope(s) have a giant covalent structure. Explain your reasoning.

    [2 marks]
    (b)

    Using the data and your knowledge, explain why C60 fullerene has a lower melting point than graphite.

    [2 marks]
    Answer and see the solution →
  2. Question 52

    1 mark · Normal

    Which statement correctly compares the electrical conductivity of diamond, graphite, and C60 fullerene?

    1. A.Only graphite conducts electricity because it has delocalised electrons.
    2. B.Only diamond conducts electricity because it has a giant covalent structure.
    3. C.Diamond and C60 fullerene both conduct electricity, but graphite does not.
    4. D.All three conduct electricity equally well.
    Answer and check →
  3. Question 53

    2 marks · Normal

    Describe the bonding in diamond in terms of the arrangement of carbon atoms and the bonds formed.

    Answer and see the solution →
  4. Question 54

    4 marks · Normal

    Diamond is a non-conductor of electricity and is very hard, while graphite is soft but conducts electricity.

    (a)

    Explain, in terms of bonding and structure, why diamond does not conduct electricity.

    [2 marks]
    (b)

    Explain, using bonding and the arrangement of atoms, why graphite is soft.

    [2 marks]
    Answer and see the solution →
  5. Question 55

    2 marks · Hard

    Diamond is used for industrial cutting tools, while graphite is used as a lubricant. Explain, in terms of structure and bonding, why graphite can be used as a lubricant but diamond cannot.

    Answer and see the solution →
  6. Question 56

    5 marks · Hard

    The three allotropes of carbon—diamond, graphite, and C60 fullerene—have different abilities to conduct electricity.

    (a)

    State which, if any, of these allotropes can conduct electricity.

    [1 mark]
    (b)

    For each allotrope, explain your answer by referring to their bonding and the movement of electrons.

    [4 marks]
    Answer and see the solution →
  7. Question 57

    2 marks · Hard

    Describe the structure and bonding in C60 fullerene, referring to how carbon atoms are arranged and bonded in this allotrope.

    Answer and see the solution →
  8. Question 58

    5 marks · Easy

    (a)

    Define a covalent bond.

    [1 mark]
    (b)

    Explain, in terms of electrostatic attraction, how a covalent bond holds two atoms together.

    [2 marks]
    (c)

    State one reason why many substances with simple molecular structures have low melting points.

    [1 mark]
    (d)

    Methane, CH, is a gas at room temperature. Explain why, using your knowledge of bonding and structure.

    [1 mark]
    Answer and see the solution →
  9. Question 59

    5 marks · Easy

    (a)

    Draw a dot-and-cross diagram to show the bonding in a molecule of hydrogen chloride (HCl).

    [2 marks]
    (b)

    State how many covalent bonds are present in a molecule of hydrogen chloride.

    [1 mark]
    (c)

    Chlorine is a gas at room temperature, but water (HO) is a liquid. Using ideas about relative molecular mass, explain this difference.

    [2 marks]
    Answer and see the solution →
  10. Question 60

    5 marks · Easy

    (a)

    Hydrogen (H) and carbon dioxide (CO) are both covalent molecules. Calculate the relative molecular mass (M) of each molecule. (Relative atomic masses: H = 1, C = 12, O = 16)

    [2 marks]
    (b)

    Which of these molecules would you expect to have a higher boiling point? Explain your answer in terms of molecular mass and intermolecular forces.

    [2 marks]
    (c)

    State the type of bonding present in both hydrogen and carbon dioxide molecules.

    [1 mark]
    Answer and see the solution →