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Pearson Edexcel International GCSE (9–1) · CHEMISTRY · Unit

Principles of Chemistry

991 practice questions

Topics covered

Practice questions

301–310 of 407 · Easy

  1. Question 301

    3 marks · Easy

    (a)

    Describe the structure of diamond in terms of the arrangement of its carbon atoms.

    [1 mark]
    (b)

    Describe the structure of graphite in terms of the arrangement of its carbon atoms.

    [1 mark]
    (c)

    State the type of structure present in C60 fullerene.

    [1 mark]
    Answer and see the solution →
  2. Question 302

    2 marks · Easy

    Diamond has a melting point of about 3550 °C, while C60 fullerene melts at about 280 °C. Use these values to explain, in terms of bonding, why diamond has such a high melting point compared to C60 fullerene.

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  3. Question 303

    2 marks · Easy

    Explain why C60 fullerene does not conduct electricity as well as graphite, referring to their structures.

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  4. Question 304

    3 marks · Easy

    Bonding and Atomic Arrangement
    Carbon AllotropeNumber of covalent bonds per carbon atomType of structure
    Diamond
    Graphite
    C60 fullerene

    Complete the table by filling in the number of covalent bonds per carbon atom and the type of structure for each allotrope.

    Answer and see the solution →
  5. Question 305

    1 mark · Easy

    State why graphite is soft.

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  6. Question 306

    3 marks · Easy

    (a)

    State the electrical conductivity for each of the following carbon structures: diamond, graphite, and C60 fullerene.

    [1 mark]
    (b)

    Explain why diamond does not conduct electricity.

    [1 mark]
    (c)

    Explain why graphite conducts electricity.

    [1 mark]
    Answer and see the solution →
  7. Question 307

    2 marks · Easy

    C60 fullerene contains 60 carbon atoms. If each carbon atom forms 3 bonds, calculate the total number of covalent bonds in one C60 molecule.

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  8. Question 308

    5 marks · Easy

    (a)

    Define a covalent bond.

    [1 mark]
    (b)

    Explain, in terms of electrostatic attraction, how a covalent bond holds two atoms together.

    [2 marks]
    (c)

    State one reason why many substances with simple molecular structures have low melting points.

    [1 mark]
    (d)

    Methane, CH, is a gas at room temperature. Explain why, using your knowledge of bonding and structure.

    [1 mark]
    Answer and see the solution →
  9. Question 309

    5 marks · Easy

    (a)

    Draw a dot-and-cross diagram to show the bonding in a molecule of hydrogen chloride (HCl).

    [2 marks]
    (b)

    State how many covalent bonds are present in a molecule of hydrogen chloride.

    [1 mark]
    (c)

    Chlorine is a gas at room temperature, but water (HO) is a liquid. Using ideas about relative molecular mass, explain this difference.

    [2 marks]
    Answer and see the solution →
  10. Question 310

    5 marks · Easy

    (a)

    Hydrogen (H) and carbon dioxide (CO) are both covalent molecules. Calculate the relative molecular mass (M) of each molecule. (Relative atomic masses: H = 1, C = 12, O = 16)

    [2 marks]
    (b)

    Which of these molecules would you expect to have a higher boiling point? Explain your answer in terms of molecular mass and intermolecular forces.

    [2 marks]
    (c)

    State the type of bonding present in both hydrogen and carbon dioxide molecules.

    [1 mark]
    Answer and see the solution →