Pearson Edexcel International GCSE (9–1) · CHEMISTRY · Unit
Principles of Chemistry
991 practice questions
Topics covered
- States of Matter102 practice questions
- Elements, Compounds and Mixtures69 practice questions
- Atomic Structure108 practice questions
- The Periodic Table103 practice questions
- Chemical Formulae, Equations and Calculations Part 119 practice questions
- Chemical Formulae, Equations and Calculations Part 2144 practice questions
- Ionic Bonding143 practice questions
- Covalent Bonding68 practice questions
- Metallic Bonding19 practice questions
- Electrolysis198 practice questions
Practice questions
201–210 of 423 · Normal
Question 201
3 marks · Normal
Answer and see the solution →A teacher claims that doubling the amount of solute added to a fixed volume of water will always double the concentration of the solution. Explain using calculations and an example whether this statement is correct.
Question 202
4 marks · Normal
Answer and see the solution →Concentration and volume data for sodium sulfate solutions Sample Concentration (mol/dm³) Volume used (dm³) A 0.10 0.020 B 0.20 0.015 C 0.40 0.025 (a)[2 marks]Which sample contains the largest amount of sodium sulfate? Show your calculations.
(b)[1 mark]State the amount in mol present in that sample.
(c)[1 mark]Suggest one reason why a higher concentration solution may have less sodium sulfate than a lower concentration solution.
Question 203
1 mark · Normal
Answer and check →Which calculation gives the concentration, in mol/dm³, of a solution containing 1.5 mol of solute in 0.75 dm³ of solution?
- A.1.5 ÷ 0.75
- B.0.75 ÷ 1.5
- C.1.5 × 0.75
- D.0.75 × 1.5
Question 204
2 marks · Normal
Answer and see the solution →Calculate the concentration in mol/dm³ of a solution containing 5.60 g of potassium hydroxide (KOH, Ar: K = 39, O = 16, H = 1) in 500 cm³ of solution.
Question 205
4 marks · Normal
Answer and see the solution →(a)[2 marks]A solution has a concentration of 1.5 mol/dm³. What is the amount (in mol) of solute in 750 cm³ of this solution?
(b)[2 marks]Describe how you would prepare 750 cm³ of this solution from a 3.0 mol/dm³ solution.
Question 206
2 marks · Normal
Answer and see the solution →Calculate the number of moles of potassium nitrate, KNO₃, in 25 cm³ of a solution with concentration 0.40 mol/dm³.
Question 207
4 marks · Normal
Answer and see the solution →A reaction between barium chloride and sodium sulfate is shown by the equation:
(a)[2 marks]Calculate the number of moles of Na₂SO₄ in 40 cm³ of solution with concentration 0.10 mol/dm³.
(b)[2 marks]Use the balanced equation to determine the number of moles of BaCl₂ that react with this amount of Na₂SO₄.
Question 208
3 marks · Normal
Answer and see the solution →What mass of magnesium sulfate, MgSO₄, is produced when 25 cm³ of 0.50 mol/dm³ sulfuric acid, H₂SO₄, reacts with excess magnesium oxide, MgO?
(Ar: Mg = 24, S = 32, O = 16)
Question 209
3 marks · Normal
Answer and see the solution →A student dissolves 0.015 mol of silver nitrate in 100 cm³ of water.
Explain how to work out the concentration of this solution in mol/dm³. Show your calculation.
Question 210
4 marks · Normal
Answer and see the solution →A student carries out a reaction between sodium hydroxide and hydrochloric acid:
Results table Experiment Volume of NaOH (cm³) Concentration of NaOH (mol/dm³) 1 20 0.25 2 15 0.25 3 25 0.50 (a)[2 marks]For experiment 2, calculate the number of moles of NaOH used.
(b)[2 marks]Using the equation, state the number of moles of HCl needed to react with the NaOH in experiment 2 and explain your answer.