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Question 393 of 991 in Principles of Chemistry

Chemical Formulae, Equations and Calculations Part 1

3 marks · Normal

A student has 21 g of magnesium chloride (MgCl2). Calculate the number of moles of MgCl2 present.

(Ar: Mg = 24, Cl = 35.5)

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0.22 mol (±0.01)

Also accept: 0.215 mol

Common mistakes: using mass instead of Mr; not using correct Mr

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Marking points

M1 · 1 mark · Calculates Mr of MgCl2: 24 + (2×35.5) = 95

M2 · 1 mark · Uses n = mass ÷ Mr

A1 · 1 mark · Correct final answer: 0.22 mol (accept answers within 0.01 of this) (follow-through)

Worked solution

Mr of MgCl2 = 24 + (2 × 35.5) = 24 + 71 = 95

Number of moles = mass / Mr = 21 g / 95 = 0.221 (rounded to 0.22 mol)

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