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Question 10 of 19 in Using the molar volume in calculations with chemical equations

Using the molar volume in calculations with chemical equations

4 marks · Normal

Hydrochloric acid reacts with sodium carbonate to produce sodium chloride, carbon dioxide and water. The balanced equation is:

(a)

Calculate the number of moles in 1.06 g of sodium carbonate. (Ar: Na = 23, C = 12, O = 16)

[2 marks]
(b)

Calculate the volume, in dm³, of carbon dioxide produced at rtp by this mass of sodium carbonate. (Molar volume at rtp = 24 dm³)

[2 marks]

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(a) 0.01 mol

(b) 0.24 dm³ dm^3

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Marking points

M1 (a) · 1 mark · Correct calculation or method for Mr(Na2CO3) (23×2 +12 +16×3 = 106)

A1 (a) · 1 mark · Correct calculation of moles (1.06/106 = 0.01 mol) (follow-through)

M2 (b) · 1 mark · Correct use of chemical equation (1:1 ratio from Na2CO3 to CO2), and use of molar volume

A2 (b) · 1 mark · Correct answer for gas volume (0.01 × 24 = 0.24 dm³) (follow-through)

Worked solution

a)

b)

From equation: 1 mol Na₂CO₃ produces 1 mol CO₂.

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