The electrolysis of copper(ii) sulfate solution using inert electrodes
2 marks · EasyIf all the copper(II) ions are removed from 100 mL of copper(II) sulfate solution by electrolysis with inert electrodes, explain and calculate what type of ions are left in the solution and what the new solution is.
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(a) SO_4^{2-} and H^+ ions · must show SO4^{2-}, H^+
(b) Dilute sulfuric acid forms · must show Sulfuric acid
Common mistakes: Confusing with sodium hydroxide; Not mentioning sulfuric acid
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Marking points
B1 · 1 mark · States SO4^{2-} and H^+ ions remain after all copper is removed.
B1 · 1 mark · States that the resulting solution is dilute sulfuric acid.
Worked solution
a) After all Cu^{2+} ions are removed, the SO4^{2-} and H^+ ions remain.
b) The new solution is dilute sulfuric acid, H2SO4.