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Question 66 of 69 in Elements, Compounds and Mixtures

Elements, Compounds and Mixtures

6 marks · Normal

A student finds a white powder in the laboratory labelled 'Sample X'. She wants to check if it is a pure substance or a mixture, and then investigate its components using paper chromatography.

(a)

Describe how the student could use melting point measurements to determine whether Sample X is pure or a mixture.

[2 marks]
(b)

The student performs a paper chromatography experiment with a spot of Sample X and three reference dyes A, B and C on the same chromatography paper. The chromatogram is developed using a suitable solvent.

The diagram below shows the results.

Geometry diagram with points Pencil line, Sample X, A, B, C, X1, X2, A1, B1, C1, Solvent frontSample XABC
Chromatogram of Sample X and reference dyes after development

The solvent front has moved 6.0 cm from the pencil line. The spots are found at the following distances above the pencil line: Sample X: 2.0 cm, 4.5 cm Dye A: 2.0 cm Dye B: 4.5 cm Dye C: 3.7 cm

(i)

How many different dyes are present in Sample X? Explain your answer.

[1 mark]
(ii)

State which reference dyes are found in Sample X. Give your reasoning.

[1 mark]
(c)

Calculate the R_f value for the spot at 3.7 cm. Show your working.

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) A pure substance has a sharp melting point, while a mixture melts over a range of temperatures. The student would heat the substance and measure its melting point. If it melts at a specific, constant temperature, it is pure; if it melts over a range, it is a mixture.

(b.i) There are two dyes in sample X, as there are two spots at different distances from the pencil line.

(b.ii) Sample X contains dyes A and B. The spots at 2.0 cm and 4.5 cm match the positions of dyes A and B on the chromatogram.

(c) Rf = 3.7 / 6.0 = 0.62 · must show Rf calculation

Common mistakes: Stating that a mixture has a sharp melting point; Mismatching dye spots by distance rather than colour and distance; Calculating Rf by dividing the wrong way round

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · States that a pure substance has a sharp (fixed) melting point, while a mixture melts over a range.

A1 (a) · 1 mark · Describes measuring the melting point/range to determine purity.

B1 (b(i)) · 1 mark · Correctly identifies number of dyes in Sample X from number of spots.

B2 (b(ii)) · 1 mark · Correctly matches Sample X spots to reference dyes with clear reasoning.

M2 (c) · 1 mark · States or uses correct Rf formula: distance moved by spot/distance moved by solvent front, with matching numbers.

A2 (c) · 1 mark · Correctly calculates Rf value (0.62, accept 0.62–0.62 with rounding). (follow-through allowed) (follow-through)

Worked solution

a) The student heats Sample X slowly and measures its melting point. If it melts at one constant temperature, it is a pure substance. If it melts over a temperature range, it is a mixture.

b) i) There are two different dyes present in Sample X, as two distinct spots are seen on the chromatogram.

ii) Dyes A and B are found in Sample X. Their spots are at the same distances (2.0 cm for A, 4.5 cm for B) as spots from Sample X.

c) The R_f value for the spot at 3.7 cm is calculated as:

R_f = 0.62

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