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Question 113 of 144 in Chemical Formulae, Equations and Calculations Part 2

The standard calculation

5 marks · Hard

A chemistry student carries out a titration to determine the concentration of a potassium hydroxide () solution. She finds that 25.0 cm³ of solution of unknown concentration reacts exactly with 20.0 cm³ of 0.200 mol/dm³ sulfuric acid (). The balanced equation for the reaction is:

Use the three-step titration calculation method to find the concentration of the solution.

(a)

Calculate the number of moles of reacted.

[1 mark]
(b)

Use the balanced equation to work out the number of moles of that reacted.

[1 mark]
(c)

Calculate the concentration of in mol/dm³.

[2 marks]
(d)

State the three-step titration calculation method used in this problem.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 0.00400 mol

(b) 0.00800 mol

(c) 0.320 mol/dm³

(d) 1) Calculate moles of known solution; 2) Use balanced equation for moles of unknown; 3) Calculate concentration using volume and moles.

Common mistakes: Incorrect volume conversion; Incorrect stoichiometric ratio; Not dividing by the correct volume when calculating concentration

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Correct calculation of moles of :

M2 (b) · 1 mark · Correct use of mole ratio (1 mol to 2 mol ) to calculate moles of : (follow-through)

M3 (c) · 1 mark · Correctly converts volume of to dm³: (follow-through)

A1 (c) · 1 mark · Accurately calculates concentration: (follow-through)

B1 (d) · 1 mark · States the three-step titration calculation method: 1) Calculate moles of known; 2) Use balanced equation; 3) Calculate concentration.

Worked solution

(a) Number of moles of :

(b) From the equation, 1 mol reacts with 2 mol , so:

(c) Concentration of :

(d) Three steps: 1) Calculate moles of known solution; 2) Use the balanced equation (mole ratio) to find moles of unknown; 3) Calculate concentration using moles and volume.

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