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Question 74 of 198 in Electrolysis

Electrolysis and redox

5 marks · Hard

The apparatus below is used to electrolyse molten tin(II) chloride (SnCl₂). Tin(II) ions (Sn²⁺) and chloride ions (Cl⁻) move towards the electrodes and react.

Apparatus: beaker (Molten SnCl2), boiling tube (Anode (+)), boiling tube (Cathode (−))Anode (+)Molten SnCl2
Electrolysis setup for molten tin(II) chloride

(a) State what is meant by 'discharging' a tin(II) ion during the electrolysis of molten tin(II) chloride.

(a)

State what is meant by 'discharging' a tin(II) ion during the electrolysis of molten tin(II) chloride.

[2 marks]
(b)

Explain, in terms of electron transfer, what happens to a tin(II) ion at the cathode in this process.

[2 marks]
(c)

Write a half-equation for the reaction involving tin(II) ions at the cathode.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Discharging a tin(II) ion means it loses its electric charge by gaining electrons to form a neutral tin atom.

(b) At the cathode, a tin(II) ion (Sn²⁺) gains two electrons (is reduced) to become a tin atom. This is reduction by electron gain.

(c) \ce{Sn^{2+} + 2e^- -> Sn} · must show Correct ionic symbols and electron transfer

Common mistakes: Mixing up cathode/anode reactions; Incorrect half-equation balancing

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Correctly explains that discharging means loss of charge (tin(II) ion becomes a neutral atom).

B2 (a) · 1 mark · Refers to gain of electrons by the tin(II) ion on discharge.

M1 (b) · 1 mark · States that Sn²⁺ gains electrons at the cathode.

A1 (b) · 1 mark · States or implies 2 electrons are gained; mentions reduction or becoming neutral atom.

B3 (c) · 1 mark · Correct half-equation: \ce{Sn^{2+} + 2e^- -> Sn}

Worked solution

a) Discharging a tin(II) ion means that it loses its electric charge by gaining electrons and forms a neutral tin atom.

b) At the cathode, each tin(II) ion gains two electrons from the electrode. This added electron transfer changes the ion (Sn²⁺) into a tin atom (Sn). This is reduction because the ion gains electrons.

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