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Question 36 of 163 in Reactivity Series

Oxidation and reduction

4 marks · Normal

Potassium chlorate(V) reacts on heating with manganese(IV) oxide catalyst:

(a)

Identify which substance is reduced and which is oxidised in this reaction.

[2 marks]
(b)

Name the oxidising agent in this reaction. Explain your answer.

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) Potassium chlorate(V) is reduced; potassium chloride is formed by reduction. Oxygen is oxidised (as O2 is evolved from KClO3). · must show KClO3 is reduced, O2/Oxygen is formed (by oxidation)

(b) Potassium chlorate(V) is the oxidising agent because it gives oxygen to other substances. · must show KClO3 is oxidising agent, justification: gives oxygen

Common mistakes: reversal of concepts

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Identifies potassium chlorate(V) is reduced.

B2 (a) · 1 mark · Identifies oxygen as the product that is oxidised (released from KClO3).

B3 (b) · 1 mark · Names potassium chlorate(V) as the oxidising agent.

B4 (b) · 1 mark · Explains this is because it gives oxygen to other substances.

Worked solution

a:

Potassium chlorate(V) is reduced as it loses oxygen.

Oxygen is formed (oxidised state, as O2 is released).

b:

Potassium chlorate(V) is the oxidising agent because it gives oxygen to other substances.

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