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Question 52 of 163 in Reactivity Series

Displacement reactions involving solutions of salts

4 marks · Normal

The table below shows observations from adding different metals to solutions of salts.

Observations of displacement reactions
Metal addedSolutionObservation
ZincCopper(II) sulfateBrown solid forms; blue solution fades
CopperSilver nitrateGrey crystals form; colourless solution turns blue
IronMagnesium sulfateNo visible change

For each reaction in the table, write the full ionic equation showing the species that change during the reaction. Where no reaction occurs, state why.

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

1) Zn(s) + Cu^{2+}(aq) -> Zn^{2+}(aq) + Cu(s); 2) Cu(s) + 2Ag^{+}(aq) -> Cu^{2+}(aq) + 2Ag(s); 3) No reaction because iron is less reactive than magnesium.

Common mistakes: Including spectator ions; Writing molecular instead of ionic equations

Show mark scheme and worked solution

Marking points

M1 · 1 mark · Correct ionic equation for Zn + Cu^{2+}; equation only includes species that change.

M2 · 1 mark · Correct ionic equation for Cu + Ag^{+}, with balancing and charges.

M3 · 1 mark · States 'no reaction' for Fe + MgSO_4 and gives correct explanation based on reactivity.

A1 · 1 mark · All formulae, charges, and balancing correct for all equations.

Worked solution

1) For zinc and copper(II) sulfate:

2) For copper and silver nitrate:

3) For iron and magnesium sulfate: no reaction – iron is less reactive than magnesium, so it cannot displace magnesium from its salt.

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