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Question 54 of 163 in Reactivity Series

Displacement reactions involving solutions of salts

2 marks · Normal

Write the ionic half-equation for the reduction that takes place when lead metal is formed from lead(II) ions.

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Pb^{2+}(aq) + 2e^- \rightarrow Pb(s)

Also accept: \ce{Pb^{2+} (aq) + 2e^- -> Pb (s)}; Pb2+(aq) + 2e- -> Pb(s)

Common mistakes: Incorrect number of electrons; Omitting state symbols

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Marking points

M1 · 1 mark · Correctly places lead(II) ions and electrons on left, lead atom on right.

A1 · 1 mark · Equaton is balanced for charge and atoms, with states.

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