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Question 5 of 19 in Reactions of metals with dilute acids

Reactions of metals with dilute acids

3 marks · Easy

The table shows the maximum temperatures reached when equal moles of different metals react with excess dilute hydrochloric acid.

Temperature changes for reactions of metals with acid
MetalInitial temperature / °CMaximum temperature / °C
Aluminium1829
Zinc1823
Iron1820
Copper1818
(a)

Calculate the temperature change for zinc.

[1 mark]
(b)

Which metal was the least reactive? Use data to support your answer.

[1 mark]
(c)

Explain why the reaction with aluminium may need to be warmed before it proceeds quickly.

[1 mark]

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(a) 5 °C · must show 23 - 18 = 5

(b) Copper; no temperature change/temperature remained at 18°C · must show Copper, cites 18°C as evidence

(c) Aluminium has a strong oxide layer which stops acid reacting quickly unless warmed. · must show Oxide layer acts as barrier

Show mark scheme and worked solution

Marking points

A1 (a) · 1 mark · Correct calculation: 23 - 18 = 5 (°C)

B1 (b) · 1 mark · Correctly identifies copper as least reactive, with relevant temperature data.

B2 (c) · 1 mark · Explains that aluminium’s oxide layer must be removed by warming to allow reaction.

Worked solution

a) Temperature change for zinc = 23 - 18 = 5°C

b) Copper is the least reactive, as its temperature remained constant at 18°C.

c) Aluminium is coated in a thin oxide layer, so the acid cannot react until this layer is removed by warming.

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