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Question 45 of 68 in Chemical Tests

Testing for chlorides (Cl^-), bromides (Br^-) and iodides (I^-)

3 marks · Easy
The table shows the precipitates formed when different halide ions react with silver nitrate.
Ion in solutionObservation after adding silver nitrate
Cl^-White precipitate
Br^-Cream precipitate
I^-Yellow precipitate

Use the information in the table to answer the following questions.

(a)

State the name and colour of the precipitate formed when a solution containing bromide ions is tested with silver nitrate.

[1 mark]
(b)

Identify which ion produces a yellow precipitate with silver nitrate.

[1 mark]
(c)

A student obtains a white precipitate when testing their solution with silver nitrate. Which halide ion is present?

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Silver bromide, cream precipitate

(b) Iodide ion (I^-)

(c) Chloride ion (Cl^-)

Common mistakes: Mixing up colours or names; Omitting precipitate name

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · States 'silver bromide' and 'cream precipitate' for bromide ions.

B2 (b) · 1 mark · Identifies iodide ion (I^-) as producing yellow precipitate.

B3 (c) · 1 mark · States chloride ion (Cl^-) for white precipitate.

Worked solution

a) The bromide ion gives a cream precipitate of silver bromide. b) The iodide ion (I^-) gives a yellow precipitate. c) If a white precipitate forms, chloride ion (Cl^-) is present.

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