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Question 82 of 86 in The Halogens

The Halogens

6 marks · Normal
(a)

Explain, with the aid of a balanced equation, what happens when sodium reacts with bromine.

[2 marks]
(b)

A student adds bromine water to a solution of potassium iodide in a test tube.

(i)

State what you would observe.

[1 mark]
(ii)

Write a balanced equation for the reaction.

[2 marks]
(iii)

Explain why bromine can displace iodine in this reaction but not chlorine.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Sodium reacts with bromine to form sodium bromide; e.g., 2Na(s) + Br2(l) \rightarrow 2NaBr(s).

(b(i)) Solution turns brown as iodine is formed.

(b(ii)) 2KI(aq) + Br2(aq) \rightarrow 2KBr(aq) + I2(aq)

(b(iii)) Bromine is more reactive than iodine, so it displaces iodine; but bromine is less reactive than chlorine, so it cannot displace chlorine.

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Describes sodium reacting with bromine to form sodium bromide.

A1 (a) · 1 mark · Correct balanced equation: 2Na(s) + Br2(l) → 2NaBr(s).

B1 (b(i)) · 1 mark · Brown color observed as iodine is formed.

M1 (b(ii)) · 1 mark · Correct reactants and products in equation.

A1 (b(ii)) · 1 mark · Equation balanced: 2KI(aq) + Br2(aq) → 2KBr(aq) + I2(aq).

B1 (b(iii)) · 1 mark · Explains bromine is more reactive than iodine (so displaces it), but less reactive than chlorine.

Worked solution

a) Sodium reacts with bromine to produce sodium bromide as follows:

b)(i) A brown color appears as iodine is produced.

b)(iii) Bromine is more reactive than iodine, so it displaces iodine, but cannot displace chlorine because chlorine is more reactive.

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