Reacting acids with bases

5 marks · Hard

Lead(II) oxide reacts with sulfuric acid in a laboratory experiment.

(a)

Name the type of chemical reaction that takes place.

[1 mark]

(b)

Give the names of the products formed in this reaction.

[2 marks]

(c)

Write a word equation for the reaction.

[1 mark]

(d)

Give a chemical symbol equation for the reaction.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) neutralisation

(b) lead(II) sulfate and water

(d) \ce{PbO(s) + H2SO4(aq) -> PbSO4(s) + H2O(l)}

Common mistakes: Incorrect naming of lead(II) sulfate as lead sulfate; Giving incomplete equations

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · States that the reaction is neutralisation.

B2 (b) · 1 mark · Names lead(II) sulfate as a product.

B3 (b) · 1 mark · Names water as a product.

B4 (c) · 1 mark · Gives the correct word equation for the reaction.

B5 (d) · 1 mark · Gives the correct balanced symbol equation.

Worked solution

a) The type of reaction is neutralisation.

b) The products are lead(II) sulfate and water.

c) Word equation: lead(II) oxide + sulfuric acid → lead(II) sulfate + water