Coding for the type of compound
3 marks · Easy(a)[1 mark]
State the number of carbon atoms in a molecule named 'butane'.
(b)[1 mark]
Write the name of the homologous series that 'butane' belongs to.
(c)[1 mark]
Give the ending that shows a compound contains a carbon–carbon double bond.
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(a) 4
(b) alkanes
(c) ene
Show mark scheme and worked solution
Marking points
B1 (a) · 1 mark · States 4 carbon atoms for butane.
B1 (b) · 1 mark · Correctly names the homologous series as 'alkanes'.
B1 (c) · 1 mark · Gives the correct ending 'ene' for double bond.
Worked solution
a) Butane has 4 carbon atoms.
b) Butane is an alkane.
c) The ending for a carbon–carbon double bond is 'ene'.