Making a polyester
3 marks · EasyThe table shows the names and structures of two monomers used to make a polyester.
| Monomer | Structural formula |
|---|---|
| Butane-1,4-diol | HOCH2CH2CH2CH2OH |
| Propane-1,3-dioic acid | HOOCCH2CH2COOH |
Identify which monomer is a diol.
State the functional group present in the acid monomer.
When these two monomers react, what type of linkage forms between them in the polyester chain?
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
Show answer
(a) Butane-1,4-diol
(b) Carboxylic acid · must show –COOH
(c) Ester link
Show mark scheme and worked solution
Marking points
B1 (a) · 1 mark · Correctly identifies 'Butane-1,4-diol' as the diol.
B2 (b) · 1 mark · States 'carboxylic acid' (–COOH) as the acid monomer's functional group.
B3 (c) · 1 mark · Identifies the linkage as an 'ester link'.
Worked solution
a) Butane-1,4-diol is the diol (it has two –OH groups). b) The functional group in the acid monomer is the carboxylic acid group (–COOH). c) The linkage formed is an ester link.