Alkenes
5 marks · EasyThe table below shows two hydrocarbon molecules.
| Molecule | Structural formula |
|---|---|
| A | CH_3CH=CH_2 |
| B | CH_3CH_2CH_3 |
Which molecule is unsaturated? Explain your answer.
State how the presence of a C=C bond affects the chemical properties of alkenes.
Describe the physical state of molecule A at room temperature.
Compare the boiling points of molecule A and molecule B.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
Show answer
(a) Molecule A; it contains a C=C double bond · must show Identification of molecule A, Explanation: presence of C=C double bond means unsaturaton
(b) It makes alkenes more reactive; allows addition reactions. · must show Alkenes are more reactive than alkanes, C=C bond allows addition reactions
(c) It is a gas at room temperature. · must show gas
(d) They have similar boiling points. · must show similar boiling points
Show mark scheme and worked solution
Marking points
A1 (a) · 1 mark · Correctly identifies molecule A as unsaturated.
A2 (a) · 1 mark · Correctly explains that molecule A contains a C=C bond making it unsaturated.
B1 (b) · 1 mark · States that the C=C bond makes alkenes more reactive / allows addition reactions.
C1 (c) · 1 mark · Correctly states molecule A is a gas at room temperature.
D1 (d) · 1 mark · States that boiling points of A and B are similar.
Worked solution
a) Molecule A is unsaturated because it has a C=C double bond; molecule B only has single C–C bonds and is saturated.
b) The C=C bond makes alkenes more reactive than alkanes and allows them to take part in addition reactions.
c) Molecule A (propene) is a gas at room temperature.
d) The boiling points of molecule A and B are very similar because both are small molecules with similar molecular masses.