Alkenes
6 marks · NormalA student finds that a colourless, flammable liquid decolourises bromine water and burns with a smoky flame.
Explain what these two observations tell you about the type of hydrocarbon present.
The student tests another liquid and observes that it does not decolourise bromine water and burns with a clean flame.
What type of hydrocarbon is this? Explain your reasoning.
Write the displayed formula for but-1-ene, the alkene that would show these observations.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
Show answer
(a) The liquid is an alkene. Decolourising bromine water means it is unsaturated (has a C=C double bond), and a smoky flame suggests incomplete combustion due to higher carbon content.
(b) The second liquid is an alkane. It does not decolourise bromine water, showing it is saturated (no C=C bond), and a clean flame is typical for alkanes, which burn more completely.
(c) Displayed formula: H2C=CH-CH2-CH3 · must show all four carbon atoms, double bond at first carbon, all bonds shown
Must show: displayed formula
Show mark scheme and worked solution
Marking points
R1 (a) · 1 mark · Identifies the hydrocarbon as an alkene/unsaturated
E1 (a) · 1 mark · Supports with both observations: decolourises bromine (C=C double bond), smoky flame (higher C by mass, incomplete combustion typical of alkene)
R2 (b) · 1 mark · Identifies the hydrocarbon as an alkane/saturated
E2 (b) · 1 mark · Explains: does not decolourise bromine water (no C=C), burns cleanly (typical for alkanes)
S1 (c) · 2 marks · Complete displayed formula (all atoms and bonds, double bond at correct position)
Worked solution
a) The decolourisation of bromine water shows the compound is unsaturated (an alkene). Burning with a smoky flame is common for alkenes due to higher C:H ratio.
b) No reaction with bromine water means the hydrocarbon is saturated (an alkane). A clean flame on burning supports this.
c) Displayed formula for but-1-ene:
H H H H | | | | H–C=C–C–C–H | | | H H H