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Question 38 of 48 in Carboxylic Acids

Carboxylic Acids

5 marks · Easy

Methanoic acid is the first member of the carboxylic acid homologous series.

(a)

Draw the displayed formula of methanoic acid.

[1 mark]
(b)

Name the salt formed when methanoic acid reacts with magnesium.

[1 mark]
(c)

Write a balanced chemical equation for the reaction between methanoic acid and magnesium.

[2 marks]
(d)

What would you observe during this reaction?

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Displayed formula: H–C(=O)–O–H, showing all bonds, with one C atom double-bonded to O and single-bonded to another O–H. · must show all bonds, -COOH group drawn fully, single C atom

(b) Magnesium methanoate

(c) Mg(s) + 2HCOOH(aq) → (HCOO)2Mg(aq) + H2(g) · must show state symbols, balanced, correct formulae

(d) Fizzing or effervescence; bubbles of hydrogen gas seen.

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Fully correct displayed formula showing all bonds for methanoic acid (COOH group clear)

B2 (b) · 1 mark · Correct name: magnesium methanoate

M1 (c) · 1 mark · Correct reactants and products, even if unbalanced (follow-through)

A1 (c) · 1 mark · Fully balanced chemical equation with correct formulae and state symbols

B3 (d) · 1 mark · Correct observation: fizzing/effervescence or hydrogen gas given off

Worked solution

a) The displayed formula of methanoic acid is:

Geometry diagram with points C, O, O, H, H
Displayed formula of methanoic acid

b) The salt formed is magnesium methanoate.

c) The balanced equation is:

d) You would observe fizzing or effervescence due to hydrogen gas being produced.

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