Introduction to Organic Chemistry
6 marks · NormalThis is the displayed formula for a compound:
Describe how the atoms are connected and identify the type of bonds present.
Give the systematic (IUPAC) name for this compound.
Suggest one homologous series this compound belongs to and give a reason for your answer.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
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(a) — · must show Four carbon chain, Single bonds between first two carbons, Double bond between carbon 3 and carbon 4, Single bonds to hydrogens
(b) but-1-ene
(c) — · must show Alkene series, Reason: contains C=C double bond
Show mark scheme and worked solution
Marking points
S1 (a) · 1 mark · Correctly describes four carbons connected in a continuous chain
S2 (a) · 1 mark · Identifies single bonds between C1–C2 and C2–C3, and double bond between C3–C4
S3 (a) · 1 mark · Mentions single covalent bonds to hydrogens on carbon atoms
N2 (b) · 2 marks · Correct IUPAC name: but-1-ene (accept 1-butene)
H1 (c) · 1 mark · Homologous series: alkene; reason: compound contains a carbon–carbon double bond
Worked solution
(a) The compound has four carbons in a straight chain. Carbon 1 is CH3, next is CH2, then CH with a double bond to CH2 at the end. There are single bonds between C1–C2 and C2–C3, a double bond between C3–C4. All remaining bonds are to hydrogen.
(b) The correct IUPAC name is but-1-ene.
(c) It belongs to the alkene homologous series because it has a carbon–carbon double bond.