SubjectCover

Question 779 of 785 in Organic Chemistry

Organic Chemistry

8 marks · Normal

This question is about the structures of alcohols and carboxylic acids.

(a)

Draw the displayed formula for propan-1-ol.

[2 marks]
(b)

Draw the displayed formula for propanoic acid.

[2 marks]
(c)

Give the molecular formula for butan-1-ol.

[1 mark]
(d)

How many carbon atoms are in a molecule of methanoic acid?

[1 mark]
(e)

Explain in one sentence how the name of an alcohol or a carboxylic acid indicates the number of carbon atoms in the molecule.

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Displayed formula for propan-1-ol: CH3–CH2–CH2–OH, all bonds shown, O–H bond drawn. · must show Three carbon chain, with –OH group on end carbon and H atoms correctly shown., All bonds shown, including O–H.

(b) Displayed formula for propanoic acid: CH3–CH2–COOH, all bonds shown, COOH group drawn with double bond to O and single bond to OH. · must show Three carbon chain, –COOH at end, all bonds shown, double bond O and single bond O–H.

(c) C4H10O

(d) 1

(e) The stem of the name (meth-, eth-, prop-, but-) tells how many carbon atoms are present; carboxylic acids always have the COOH group at the end. · must show name stem gives number of carbons, COOH group always at end for acids

Show mark scheme and worked solution

Marking points

A1 (a) · 2 marks · Award 2 marks for a fully correct displayed formula for propan-1-ol with all bonds shown, including O–H. Award 1 mark for correct structure but incomplete or missing bonds.

A2 (b) · 2 marks · Award 2 marks for a fully correct displayed formula for propanoic acid with all bonds shown, COOH group detailed with double bond O and single bond O–H. Award 1 mark for correct structure but incomplete or missing bonds.

B1 (c) · 1 mark · C4H10O only.

B2 (d) · 1 mark · One only.

E1 (e) · 2 marks · 1 mark for mentioning the name stem gives carbon number, 1 mark for stating COOH group is always at end (for acids) or –OH group position is specified (for alcohols).

Worked solution

a) Propan-1-ol displayed formula:

Geometry diagram with points C, C, C, O, H, H, H, H, H, H, H
Displayed formula for propan-1-ol

b) Displayed formula for propanoic acid:

Geometry diagram with points C, C, C, O, O, H, H, H, H, H, H
Displayed formula for propanoic acid

c) Butan-1-ol: its molecular formula is C4H10O.

d) Methanoic acid has one carbon atom.

e) The stem of the compound's name (such as meth-, eth-, prop-, but-) tells how many carbon atoms are present in the molecule. For carboxylic acids, the COOH group is always attached to the end carbon in the chain.

Report a problem with this question
What's wrong?
CHEMISTRY question: Organic Chemistry | SubjectCover