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Question 17 of 18 in Alkanes

Alkanes

5 marks · Hard

This question is about unbranched alkanes.

(a)

Draw the displayed (structural) formula of the straight-chain alkane with eight carbon atoms.

[2 marks]
(b)

Write the name of this alkane.

[1 mark]
(c)

State the molecular formula for this compound.

[1 mark]
(d)

How many single carbon–carbon bonds are present in one unbranched molecule of this alkane? Show your reasoning.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) — · must show 8 carbon atoms in a straight chain, 18 hydrogens correctly attached

(b) octane · must show octane

(c) C8H18 · must show C8H18

(d) 7 · must show States 7 single C–C bonds, Reasoning: one fewer C–C bond than number of carbon atoms

Must show: a straight C8 chain, all hydrogens shown, name: octane, formula: C8H18, bond count: 7

Also accept: For the displayed formula, zig-zag or linear structure accepted as long as all atoms/bonds correct

Common mistakes: Branched structure; Wrong count for number of bonds

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Draws 8 carbons in a single straight chain, all C–C bonds shown

B2 (a) · 1 mark · All 18 hydrogens correctly attached to carbons; no extra/missing H

B3 (b) · 1 mark · Correct name: octane

B4 (c) · 1 mark · Correct molecular formula: C8H18

B5 (d) · 1 mark · Correctly states 7 single C–C bonds and gives logical reasoning (i.e., 8 carbons linked = 7 bonds) (follow-through)

Worked solution

a) The displayed formula for the straight-chain alkane with eight carbon atoms shows 8 carbons joined in a row with single bonds, each carbon attached to enough hydrogens to make 4 bonds in total per carbon, for example:

H–C–C–C–C–C–C–C–C–H, with hydrogens on all free valencies (each end carbon with 3 hydrogens, inner carbons with 2 each).

b) Name: octane

c) Molecular formula: C8H18

d) There are 7 single carbon–carbon bonds present. Reason: Each pair of adjacent carbons forms one C–C bond; for 8 carbons in a line, that is 8–1 = 7 bonds.

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