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Question 14 of 19 in Endothermic reactions

Endothermic reactions

2 marks · Normal

When 0.10 mol of solid ammonium nitrate, , dissolves in water, the temperature of the water decreases as 3.40 kJ of heat is absorbed from the surroundings.

Calculate the molar enthalpy change, , for the dissolution of ammonium nitrate in kJ/mol. Include the correct sign.

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-34 kJ/mol (±1)

Also accept: +34 kJ/mol (if sign explained as endothermic/absorbed); -34.0 kJ/mol

Common mistakes: Using wrong sign for endothermic process; Not scaling to per mole

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Marking points

M1 · 1 mark · Correct method: divides energy by moles to find molar enthalpy change. Accept correct rearrangement or unit conversion.

A1 · 1 mark · Correct final value and sign: –34 kJ/mol (or equivalent, with sign explained for endothermic direction, allow rounding). Unit required for full mark.

Worked solution

Heat absorbed, kJ; moles of ammonium nitrate = 0.10 mol.

Molar enthalpy change:

As heat is absorbed from the surroundings (temperature decreases), the process is endothermic. So, kJ/mol or –34 kJ/mol, depending on convention (usually shown as positive for endothermic, negative for exothermic).

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