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Question 12 of 18 in Calorimetry experiments for determining the enthalpy changes of reactions

Calorimetry experiments for determining the enthalpy changes of reactions

4 marks · Normal

The table shows some data from a calorimetry experiment measuring the enthalpy change of a displacement reaction between iron and copper(II) sulfate:

Data from calorimetry experiment
Volume of copper(II) sulfate solution / cm³Mass of iron used / gInitial temperature / °CMaximum temperature / °CSpecific heat capacity / J/g°C
602.418.424.74.18
(a)

Calculate the temperature change (ΔT) for this reaction.

[1 mark]
(b)

Assume the density of the solution is 1 g/cm³. Calculate the heat energy change, Q, in joules.

[2 marks]
(c)

Suggest one assumption made in this calculation.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 6.3 °C

(b) 1579 J

(c) Assuming the specific heat capacity of the solution is the same as that of water.

Common mistakes: not converting units; using mass of Fe instead of solution

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Marking points

A1 (a) · 1 mark · Correct calculation of ΔT: 24.7 - 18.4 = 6.3°C

M1 (b) · 1 mark · Substitutes correct mass (60 g), s.h.c. (4.18), and ΔT (6.3) into Q = mcΔT. (follow-through)

A2 (b) · 1 mark · Obtains Q = 60 × 4.18 × 6.3 = 1579 J (accept small rounding errors). (follow-through)

B1 (c) · 1 mark · Suggests any suitable assumption, e.g., s.h.c. same as water, density same as water, all heat goes to solution.

Worked solution

(a) ΔT = 24.7 - 18.4 = 6.3°C

(b) Q = mcΔT = 60 g × 4.18 J/g°C × 6.3°C = 1579 J

(c) One assumption is that the specific heat capacity of the solution is the same as water's.

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