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Question 69 of 144 in Reversible Reactions and Equilibria

Changing the pressure

4 marks · Normal

Consider the following data collected for this equilibrium reaction:

Condition% M(g)% N(g)% Q(g)
Low pressure404020
High pressure454510
(a)

What is the total number of moles of gas on each side of the equation?

[1 mark]
(b)

Describe the effect that increasing pressure has on the amounts of M(g), N(g), and Q(g).

[2 marks]
(c)

Explain your answer to (b) in terms of the number of gas molecules.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Left: 2 moles of gas (M and N), Right: 1 mole of gas (Q).

(b) Increasing pressure increases % of M and N, decreases % of Q.

(c) The equilibrium shifts to the left (side with more gas molecules) when pressure increases.

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Correctly states number of moles of gas on each side.

B2 (b) · 1 mark · States percentage of Q decreases when pressure increases.

B3 (b) · 1 mark · States percentage of M and N increase when pressure increases.

B4 (c) · 1 mark · Links change to the side with more gas molecules.

Worked solution

a) Left side: 1 (M) + 1 (N) = 2 moles of gas; right side: 1 (Q) = 1 mole.

b) When pressure increases from low to high, percentage of Q decreases (from 20% to 10%). Percentages of M and N increase (40% to 45%).

c) Increasing pressure favours the side with fewer gas molecules; here, the right side has fewer (1), so equilibrium shifts towards M and N on the left.

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CHEMISTRY question: Changing the pressure | SubjectCover