SubjectCover

Question 128 of 144 in Reversible Reactions and Equilibria

The effect of concentration

4 marks · Normal

The following reaction is at equilibrium in a closed container: A chemist adds more C to the equilibrium mixture.

(a)

Predict the effect of adding more C on the position of equilibrium. (1)

[1 mark]
(b)

Explain your answer to part (a). (2)

[2 marks]
(c)

Suggest one way the chemist could adjust the conditions to increase the yield of D. (1)

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) The equilibrium shifts to the left (towards reactants).

(b) According to Le Chatelier’s principle, increasing the concentration of a product (C) causes the system to oppose the change by shifting towards the reactants, using up some C.

(c) Remove D from the mixture as it forms, or increase the concentration of A or B.

Common mistakes: Saying the equilibrium does not move; Giving an incorrect direction of shift

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · States that the equilibrium shifts to the left/towards reactants.

M1 (b) · 1 mark · Correctly refers to increase in concentration of product as the cause.

M2 (b) · 1 mark · Explains the system opposes the change by shifting equilibrium to use up added C (towards reactants).

B2 (c) · 1 mark · Suggests removal of D or increasing A/B to increase yield of D.

Worked solution

(a) The equilibrium shifts to the left towards the reactants.

(b) Adding C increases the concentration of a product. The equilibrium will oppose this change by shifting to remove some of the added C. Therefore, more A and B will form from C and D.

(c) To increase the yield of D, the chemist can remove D as it forms or increase the amount of A or B.

Report a problem with this question
What's wrong?