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Question 60 of 144 in Reversible Reactions and Equilibria

Changing the pressure

2 marks · Easy

For the following equilibrium reaction, calculate the difference in the total number of gaseous molecules between the left and right sides.

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2 (±0)

Common mistakes: 4; 1; 3

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Marking points

M1 · 1 mark · Counts total moles of gas on each side (left: 3 + 1 = 4, right: 2)

A1 · 1 mark · Gives final answer: 2

Worked solution

Left side: 3 (A) + 1 (B) = 4 gaseous molecules. Right side: 2 (C) = 2 gaseous molecules. Difference = 4 3 = 2.

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