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Question 64 of 144 in Reversible Reactions and Equilibria

Changing the pressure

3 marks · Easy

Consider the following equilibrium, which is carried out in a sealed container:

(a)

State the number of gas molecules on the left and the right side of the equation.

[1 mark]
(b)

State what will happen to the equilibrium position if the pressure is increased.

[1 mark]
(c)

Give a reason for your answer to part (b).

[1 mark]

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(a) Left: 2, Right: 2

(b) There is no effect / No change to the position of equilibrium

(c) Because there are equal numbers of gas molecules on both sides, changing the pressure does not affect the equilibrium.

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Marking points

B1 (a) · 1 mark · States numbers: 2 on left, 2 on right

B1 (b) · 1 mark · States that increasing pressure has no effect

B1 (c) · 1 mark · Gives a correct explanation based on equal gas molecules

Worked solution

(a) There are 2 gas molecules on both sides (left: 2X(g); right: Y(g) and Z(g)).

(b) Increasing the pressure has no effect on the equilibrium position.

(c) Because both sides have two gas molecules, the equilibrium is not affected by pressure.

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