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Question 246 of 442 in Physical Chemistry

How does a catalyst work?

3 marks · Normal

A reaction has reactants at an energy level of 95 kJ/mol, a peak (without a catalyst) at 155 kJ/mol, and products at 65 kJ/mol.

A catalyst provides an alternative pathway with a peak at 110 kJ/mol.

Calculate:

(a)

The activation energy without a catalyst.

[1 mark]
(b)

The activation energy with a catalyst.

[1 mark]
(c)

The difference in activation energy caused by the catalyst.

[1 mark]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 60 kJ/mol

(b) 15 kJ/mol

(c) 45 kJ/mol

Common mistakes: Subtracting product from peak instead of reactant from peak; Forgetting the difference is always positive

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Marking points

M1 (a) · 1 mark · Correct subtraction: activation energy (without catalyst) = peak (without catalyst) - reactants (155 - 95).

A1 (b) · 1 mark · Correct subtraction: activation energy (with catalyst) = peak (with catalyst) - reactants (110 - 95).

A2 (c) · 1 mark · Difference in activation energy = answer to (a) - answer to (b) (allow follow through). (follow-through)

Worked solution

a) Activation energy without catalyst = peak (no catalyst) - reactants = 155 kJ/mol - 95 kJ/mol = 60 kJ/mol.

b) Activation energy with catalyst = peak (with catalyst) - reactants = 110 kJ/mol - 95 kJ/mol = 15 kJ/mol.

c) Difference = (activation energy without) - (activation energy with) = 60 kJ/mol - 15 kJ/mol = 45 kJ/mol.

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