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Question 12 of 20 in Graphs 1

Graphs 1

3 marks · Normal

Find the equation of the straight line that passes through the points (1, 5) and (3, 9). Give your answer in the form y = mx + c.

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y = 2x + 3

Must show: Gradient calculated correctly, Substitution for c, Final answer y = 2x + 3

Common mistakes: Substituting values incorrectly

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Marking points

M1 · 1 mark · Calculates gradient: m = (9-5)/(3-1) = 2

M2 · 1 mark · Uses point and m to form y = mx + c, finds c = 3

A1 · 1 mark · Final answer y = 2x + 3 (follow-through)

Worked solution

Gradient: m = (9 – 5)/(3 – 1) = 4/2 = 2

Substitute (1, 5) into y = mx + c: 5 = 2 × 1 + c ⇒ c = 3

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MATHEMATICS A question: Graphs 1 | SubjectCover