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Question 18 of 20 in Graphs 1

Graphs 1

4 marks · Hard

The straight line L passes through the points (–5, 7) and (3, –9).

(a)

Calculate the gradient of line L.

[2 marks]
(b)

Find the equation of line L in the form .

[2 marks]

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(a) -2

(b) y = -2x - 3

Common mistakes: Sign errors in gradient; Using wrong coordinates to find y-intercept

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Marking points

M1 (a) · 1 mark · Correct substitution into gradient formula ().

A1 (a) · 1 mark · Correct calculation of gradient as -2.

M2 (b) · 1 mark · Uses correct gradient with one point to substitute into or equivalent method. (follow-through)

A2 (b) · 1 mark · Gives final equation as . (follow-through)

Worked solution

a) Gradient =

b) Use point (3, –9):

Equation:

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