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Question 88 of 105 in Unit 2

Handling Data 1

5 marks · Hard

A television station surveyed 120 viewers about their favourite type of programme: Sports, News, Drama, or Comedy. Their results are summarised as follows:

Programme typeFrequency
Sports37
News19
Drama46
Comedy18
(a)

Calculate the mean number of viewers per programme type.

[1 mark]
(b)

The head of the station claims the survey shows most viewers like Drama. Is this justified? Support your answer with calculations.

[2 marks]
(c)

If the station wants to advertise to the largest possible audience, which average should they use and why?

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Mean = 120/4 = 30 · must show Sum of 37, 19, 46, 18 = 120; 120 ÷ 4 = 30

(b) Drama has the highest frequency (46/120 = 38.3%), but this is not more than half, so most viewers do not prefer Drama. Claim is not justified. · must show Percent for Drama ≈ 38% < 50%; so 'most' is incorrect

(c) They should use the mode (Drama, 46), because it represents the most popular single category, not the mean or median, which do not reflect popularity in categories. · must show States mode, Justifies as reflecting most popular category

Also accept: For part (a): Accept rounding to 1 decimal place

Common mistakes: Dividing by 120, not by 4 for mean; Not connecting mode to most popular item

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Adds frequencies and divides by number of categories (4)

B1 (b) · 1 mark · Calculates Drama percentage: 46/120 = 38.3% (follow-through)

E1 (b) · 1 mark · Rejects 'most' claim; explains it's not more than half (follow-through)

B2 (c) · 1 mark · Correctly identifies mode as best average for category popularity

E2 (c) · 1 mark · Explains the choice based on what mode represents in this context

Worked solution

a. Mean per programme type: (37 + 19 + 46 + 18) ÷ 4 = 120 ÷ 4 = 30 viewers.

b. Drama: 46/120 ≈ 0.383 = 38.3%. 'Most' requires more than 50%. Claim is not justified.

c. The mode (Drama, 46 viewers) shows the most popular single category; mean/median would not pinpoint popularity.

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