Handling Data 3
3 marks · NormalThe test scores of 6 students are:
| Student | Score |
|---|---|
| A | 71 |
| B | 73 |
| C | 67 |
| D | 73 |
| E | 75 |
| F | 74 |
Complete the table by adding two rows for the mode and mean of these test scores. Give your answers in the table.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
Show answer
Must show: Mode: 73, Mean: 72.166… or equivalent decimal
Also accept: Mean rounded correctly (to 1 or 2 dp)
Common mistakes: Stating 'mode' as a value not present more than once; arithmetic error in mean
Show mark scheme and worked solution
Marking points
M1 · 1 mark · Correct method for mode and mean stated or implied.
A1 · 1 mark · Correct value for mode (73) written in table.
A2 · 1 mark · Correct value for mean, rounded appropriately (72.2 or 72.17 or full fraction).
Worked solution
Scores: 71, 73, 67, 73, 75, 74
Mode: 73 (occurs twice)
Mean = (71 + 73 + 67 + 73 + 75 + 74)/6 = 433/6 = 72.166... (72.2 to 1 dp)