Question 9 of 18 in Algebra 5

Algebra 5

4 marks · Normal

Solve the quadratic equation:

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x=3,\ x=4

Also accept: x=4,\ x=3

Common mistakes: x=-3,\ x=-4

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Marking points

M1 · 1 mark · Attempt to factorise as (x - a)(x - b).

M2 · 1 mark · Correct factors found: (x - 3)(x - 4).

M3 · 1 mark · Set each bracket to zero and solve for x.

A1 · 1 mark · Both solutions x = 3 and x = 4 clearly given (any order).

Worked solution

We factorise:

Set each bracket to zero:

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