SubjectCover

Question 16 of 18 in Number 5

Number 5

4 marks · Hard

A scientist measures the mass of a metal rod to be 756.7 g to the nearest gram and its length to be 120.5 cm to the nearest 0.1 cm.

(a)

Write down the lower and upper bounds for the mass and length measurements.

[2 marks]
(b)

Calculate the minimum and maximum possible density of the rod in g/cm³. Density = Give both answers correct to 3 significant figures.

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) Mass: lower bound = 756.5 g, upper bound = 757.5 g; Length: lower bound = 120.45 cm, upper bound = 120.55 cm

(b) Minimum density = 756.5 ÷ 120.55 = 6.278 g/cm³ (to 3 s.f. = 6.28 g/cm³); Maximum density = 757.5 ÷ 120.45 = 6.288 g/cm³ (to 3 s.f. = 6.29 g/cm³)

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Correct identification of lower and upper bounds for mass and/or length.

A1 (a) · 1 mark · All four correct bounds clearly stated.

M2 (b) · 1 mark · Correct substitution into density formula using suitable bounds.

A2 (b) · 1 mark · Both minimum and maximum densities calculated correctly and rounded to 3 significant figures. (follow-through)

Worked solution

a) Lower bound for mass = 756.7 − 0.5 = 756.2 g, upper bound = 756.7 + 0.5 = 757.2 g. But since standard answers take 'nearest gram', bounds are 756.5 g (lower), 757.5 g (upper).

Lower bound for length = 120.5 − 0.05 = 120.45 cm, upper bound = 120.5 + 0.05 = 120.55 cm.

b) Minimum density = lowest mass ÷ highest length = 756.5 ÷ 120.55 = 6.278 g/cm³ (to 3 s.f. = 6.28 g/cm³).

Maximum density = highest mass ÷ lowest length = 757.5 ÷ 120.45 = 6.288 g/cm³ (to 3 s.f. = 6.29 g/cm³).

Report a problem with this question
What's wrong?