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Question 101 of 104 in Unit 5

Unit 5

7 marks · Normal

The graph below shows the curve .

y = x² - 4-4-3-2-101234-6-4-20246xyy = x² - 4
Quadratic curve y = x² - 4
(a)

State the points where the curve cuts the x-axis.

[1 mark]
(b)

Use the graph or otherwise to write down the equation solved at the y-intercept. Find the y-intercept.

[2 marks]
(c)

Describe the transformation that maps the graph of to the graph of .

[2 marks]
(d)

Solve the inequality . Give the solution set for .

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) (-2, 0) and (2, 0) · must show Both x-intercepts

(b) Equation: y = x² - 4 when x = 0; y-intercept is (0, -4). · must show Substitute x=0 to find y

(c) Translation 2 units to the right. · must show Translation right

(d) -2 < x < 2 · must show Correct solution set for the inequality

Show mark scheme and worked solution

Marking points

B1 (a) · 1 mark · Both correct x-intercepts identified; values must be exact.

M1 (b) · 1 mark · Substitutes x=0 to form correct equation.

A1 (b) · 1 mark · Gives correct y-intercept.

B2 (c) · 2 marks · Correctly states it is a translation right by 2 units.

M2 (d) · 1 mark · Sets up and solves x^2 - 4 < 0 (i.e. finds values for x^2 < 4).

A2 (d) · 1 mark · Gives final solution -2 < x < 2.

Worked solution

a) The curve crosses the x-axis where y=0: x^2-4=0 ⇒ x^2=4 ⇒ x=±2. Points: (-2, 0) and (2, 0).

b) At x=0: y=0^2-4=-4, so y-intercept is (0, -4).

c) y = (x-2)^2 - 4 is a translation of y = x^2 - 4 by 2 units to the right.

d) x^2-4 < 0 ⇒ x^2 < 4 ⇒ -2 < x < 2.

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