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Question 14 of 18 in Sequences

Sequences

2 marks · Normal

Given the sequence 4, 9, 16, 25, 36, ..., write a formula for the nth term.

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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a_n = n^2 + 3

Also accept: n^2 + 3; a_n = n^2 + 3

Common mistakes: Writing n^2 instead of n^2 + 3

Show mark scheme and worked solution

Marking points

M1 · 1 mark · Spots correct pattern (square numbers plus 3) or relates terms to n.

A1 · 1 mark · Writes correct nth term formula a_n = n^2 + 3 (or equivalent).

Worked solution

First term: 4 (when n=1); Second term: 9 (n=2); etc. Compare with n^2: 1^2=1, 2^2=4, 3^2=9, etc.

Wait, let's list values:

nTermn^2
141
294
3169
42516
53625

The terms are exactly (n+1)^2, since 2^2=4, 3^2=9, 4^2=16, 5^2=25, 6^2=36.

So the nth term is (n + 1)^2.

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