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Question 6 of 16 in Shape and Space 6

Shape and Space 6

4 marks · Normal
Geometry diagram with points O, A, B, COABC
Diagram for Question 1

In the diagram, O is the centre of the circle. The radius of the circle is 5 cm. AB and AC are chords of the circle and angle BAC = 32°.

(a)

Find the size of angle BOC. Give a reason for your answer.

[2 marks]
(b)

Calculate the length of the chord BC. Give your answer to 2 decimal places.

[2 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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(a) 64° (Angle at centre is twice angle at the circumference) ° · must show twice the angle at circumference

(b) 8.98 cm · must show cosine rule

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · States that the angle at the centre is twice the angle at the circumference.

A1 (a) · 1 mark · Correctly calculates angle BOC as 64°.

M2 (b) · 1 mark · Attempts cosine rule to find BC using correct or ft angle. (follow-through)

A2 (b) · 1 mark · Obtains BC = 8.98 cm (2 dp). Accept values 8.97 to 8.99. (follow-through)

Worked solution

(a) Angle at centre theorem: angle at centre is twice the angle at the circumference.

(b) Use cosine rule in triangle BOC:

Correction: Cosine rule should be between B and C, with angle BAC subtended, using 5 and 5 and included angle 64°. Therefore:

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