Sets 3
2 marks · EasySet A = {students who play guitar}, Set B = {students who play piano}, in a class of 28 students. Explain using set notation how you would find the number of students who play either guitar or piano, but not both.
Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.
Show answer
n((A \ B) ∪ (B \ A)) or n(A ∪ B) − n(A ∩ B)
Also accept: n(A ∪ B) − n(A ∩ B); n((A \ B) ∪ (B \ A)); n((A ∪ B) \ (A ∩ B))
Common mistakes: Giving just n(A ∪ B) or n(A) + n(B)
Show mark scheme and worked solution
Marking points
M1 · 1 mark · Correctly identifies that students who play either but not both are those in A or B minus those in both (the intersection).
A1 · 1 mark · Writes the set operation as n((A ∪ B) − (A ∩ B)), n((A \ B) ∪ (B \ A)), or equivalent.
Worked solution
The number of students who play either guitar or piano but not both is given by
Alternatively, it equals n(A ∪ B) minus n(A ∩ B):