Handling Data 5
2 marks · NormalA fair die is thrown twice. What is the probability of getting at least one six in the two throws?
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11/36 (±0.01)
Also accept: 0.306 (3 sf)
Common mistakes: Forgetting to use 1 – P(no six); Incorrectly using addition of single probability
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Marking points
M1 · 1 mark · Finds probability of no six: 5/6 × 5/6 = 25/36, then complements.
A1 · 1 mark · Gives final answer 11/36 or correct decimal equivalent.
Worked solution
Probability of no six on each throw: 5/6
Probability of at least one six = 1 − 25/36 = 11/36