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Question 47 of 108 in Unit 10

Graphs 9

3 marks · Normal

A particle moves along a straight line and its displacement from a fixed point at time seconds is given by .

Explain how you would find the velocity and acceleration of the particle at . Write down the values.

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

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Velocity at t=2: -2 m/s; Acceleration is constant at 4 m/s^2

Also accept: Velocity: -2 m/s, acceleration: 4 m/s^2

Common mistakes: Substituting the value before differentiating; Forgetting to differentiate twice for acceleration

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Marking points

M1 · 1 mark · States or uses that velocity is the first derivative of displacement.

A1 · 1 mark · Finds correct velocity at as -2 m/s.

A2 · 1 mark · Correctly finds acceleration as 4 m/s^2.

Worked solution

Velocity is the first derivative of s: .

At , .

Acceleration is the derivative of velocity: .

So acceleration is 4 m/s^2 at all times.

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