Shape and Space 10

3 marks · Normal

Find all values of between and such that . Give your answers in degrees.

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30°, 150° degrees (±1)

Must show: Both solutions between 0° and 360°

Also accept: 30, 150

Common mistakes: Only giving one solution; Forgetting sine is positive in both Q1 and Q2

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Marking points

M1 · 1 mark · Method: Sets so .

M2 · 1 mark · Finds alternative angle: .

A1 · 1 mark · Both correct answers: 30°, 150°.

Worked solution

gives (quadrant 1).

Also, sine is positive in quadrant 2: .

So, solutions in 0° to 360° are 30°, 150°.