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Pearson Edexcel International GCSE (9–1) · MATHEMATICS A · Unit

Unit 10

108 practice questions

Topics covered

Practice questions

21–30 of 41 · Easy

  1. Question 21

    1 mark · Easy

    What is the value of the gradient at a stationary point of a curve?

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  2. Question 22

    1 mark · Easy

    Write down the formula for the area of a triangle when two sides are of length and and the included angle is .

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  3. Question 23

    2 marks · Easy

    Calculate the value of .

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  4. Question 24

    2 marks · Easy

    In triangle XYZ, sides XY = 9 cm, XZ = 7 cm, and YZ = 12 cm. Angle YXZ is opposite side YZ. Can you use the sine rule to find angle YXZ? Explain your answer.

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  5. Question 25

    3 marks · Easy

    The triangle below has sides PQ = 5.0 cm and QR = 6.0 cm, and angle PQR = 60°.

    Geometry diagram with points P, Q, RPQR
    Triangle PQR (not to scale)
    (a)

    Write down the lengths of the two sides and the angle needed to calculate the area of triangle PQR using trigonometry.

    [1 mark]
    (b)

    Calculate the area of triangle PQR, giving your answer to 2 decimal places.

    [2 marks]
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  6. Question 26

    3 marks · Easy

    The table below gives values for the function . Complete the missing values for and .

    Values for \( y = \sin \theta \)
    (degrees)
    0
    90
    180
    270
    360
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  7. Question 27

    1 mark · Easy

    State whether the sine rule or cosine rule would be used to find the third side of a triangle when you know two sides and the included angle.

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  8. Question 28

    2 marks · Easy

    Calculate the area of a triangle with sides 9.0 cm and 4.5 cm and included angle 45°. Give your answer to 2 decimal places.

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  9. Question 29

    2 marks · Easy

    A coin is tossed twice. Calculate the probability that both tosses show heads. Give your answer as a decimal.

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  10. Question 30

    2 marks · Easy

    A bag contains 1 red, 2 blue and 3 green counters. You take one at random, replace it, and then take a second counter at random. Explain why a tree diagram can be used to represent all possible outcomes for this problem.

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