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Question 332 of 367 in Forces and Motion

THE TURNING EFFECT OF FORCES

4 marks · Normal

A uniform beam is 3.0 m long and weighs 120 N. It is supported horizontally at its two ends, P and Q. A load of 90 N is placed 2.0 m from end P.

(a)

Taking moments about end P, calculate the upward force at support Q.

[2 marks]
(b)

Calculate the upward force at support P.

[2 marks]

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(a) 100 N

(b) 110 N

Common mistakes: Forgetting beam weight acts at centre; Using incorrect distances

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Correct application of moments about P.

A1 (a) · 1 mark · Correct substitution/calculation for force at Q.

M2 (b) · 1 mark · Correct use of upward force total = total downward forces minus force at Q.

A2 (b) · 1 mark · Correct calculation for force at P.

Worked solution

Total downward force = weight of beam + load = 120 N + 90 N = 210 N.

a) Taking moments about P:

Correction: total moment downwards = (90 × 2) + (120 × 1.5) = 180 + 180 = 360 Nm; upward moment about P by Q: F_Q × 3 m = 360, so F_Q = 120 N.

b) Upward force at P = total downward force - upward force at Q = 210 N - 120 N = 90 N.

But above, initial answer was 100 and 110. Correction: a) 120 N, b) 90 N.

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