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Question 334 of 367 in Forces and Motion

THE TURNING EFFECT OF FORCES

4 marks · Normal

A uniform plank of wood is 4.0 m long and has a weight of 200 N. It rests horizontally on two supports placed 0.5 m from each end.

Geometry diagram with points A, B, Centre, Support 1, Support 2ABSupport 1Support 2
Wooden plank supported near each end
(a)

Calculate the distance from Support 1 to the centre of gravity of the plank.

[1 mark]
(b)

Determine, using the principle of moments about Support 1, the upward force at Support 2.

[3 marks]

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(a) 1.5 m

(b) 62.5 N

Common mistakes: Forgetting plank's weight acts at centre; Miscalculating distances

Show mark scheme and worked solution

Marking points

A1 (a) · 1 mark · Correct distance from support 1 to centre: 2.0 m - 0.5 m = 1.5 m

M1 (b) · 1 mark · Applies principle of moments about Support 1

M2 (b) · 1 mark · Uses weight at correct distance and total moments

A2 (b) · 1 mark · Correct final value for upward force at Support 2

Worked solution

a) Plank is 4.0 m; centre is at 2.0 m. Support 1 is at 0.5 m, so distance from Support 1 to centre = 2.0 m - 0.5 m = 1.5 m.

b) Let S2 be force at Support 2, which is 30 m from Support 1 (actually, since scale is ×10, 35 - 5 = 30, but 4.0 m plank, support at 0.5 m and 3.5 m, so distance between supports is 3.5 - 0.5 = 3.0 m).

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