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Question 218 of 367 in Forces and Motion

HOOKE'S LAW

3 marks · Normal

A metal wire is stretched by attaching weights. The original length of the wire is 50.0 cm. With a 10 N force, the length becomes 50.8 cm.

(a)

Calculate the extension of the wire.

[1 mark]
(b)

If the extension is proportional to the force for this wire, what would its length be when a 25 N force is applied?

[2 marks]

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(a) 0.8 cm

(b) 52.0 cm

Common mistakes: Reversing subtraction when finding extension; Incorrect use of ratio for proportionality

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Marking points

A1 (a) · 1 mark · Correct calculation of extension: 50.8 cm – 50.0 cm = 0.8 cm.

M1 (b) · 1 mark · Finds extension for 25 N using proportionality (sets up correct ratio/calculation). (follow-through)

A2 (b) · 1 mark · Gives correct new length: 52.0 cm (adds calculated extension to original length). (follow-through)

Worked solution

(a) Extension = 50.8 cm – 50.0 cm = 0.8 cm.

(b) 10 N causes 0.8 cm extension. Force and extension are proportional.

x = (0.8 / 10) × 25 = 2.0 cm extension.

So, new length = 50.0 cm + 2.0 cm = 52.0 cm.

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