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Question 14 of 97 in Movement and Position

Distance-time graphs

5 marks · Normal

A student times a remote-control car moving along a straight track. The car starts from rest at point A and moves at a steady speed until it reaches point B, 40 m away. It takes 25 seconds to get from A to B.

(a)

Calculate the average speed of the car as it moves from A to B. Give your answer in m/s.

[2 marks]
(b)

After stopping at B for 15 seconds, the car returns with the same average speed to A. Draw the distance–time graph for the whole journey from A to B to A, labelling axes with units and marking the time points where the car changes direction or is stationary.

[3 marks]

Work this out on paper, then compare with the answer and worked solution below. With a free account you can submit written answers for marking.

Show answer

(a) 1.6 m/s

(b) — · must show Y-axis labelled distance (m), X-axis labelled time (s), first section: straight line from (0,0) to (25,40), steady slope, horizontal line from (25,40) to (40,40), showing car stopped, straight declining line from (40,40) to (65,0), return to A

Common mistakes: swapping distance and time; not labelling axes on graph; not including stationary period

Show mark scheme and worked solution

Marking points

M1 (a) · 1 mark · Substitute correct values into speed = distance/time

A1 (a) · 1 mark · Calculates correct value with correct unit (1.6 m/s)

B1 (b) · 1 mark · Axes correctly labelled with units (distance in m, time in s)

B2 (b) · 1 mark · Graphs outbound journey A to B (0,0) to (25,40) as straight line

B3 (b) · 1 mark · Shows stationary period at B, then straight return to A ending at (65,0)

Worked solution

a) To calculate the average speed:

b) The graph should: - Start at (0,0), increase steadily to (25,40) (outbound journey) - Stay flat from (25,40) to (40,40) (stationary) - Decline steadily from (40,40) to (65,0) (return journey) - Y-axis: distance (m); X-axis: time (s).

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